Well you are going from a primary alcohol to an aldehyde so you are doing an oxidation. That eliminates b, c, and d. That leaves a or e. CrO3/H+, K2CrO7/H+ and KMnO4 are all strong oxidizers so they will oxidize the primary alcohol to a carboxylic acid which of course is not the product. PCC however, is a more mild oxidizer that will stop at the aldehyde level of oxidation giving you 2-methylpropanal. So, long story short....the answer is A.
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